Warm-up
Three quick questions from earlier lessons.
Discover
With only a compass and a straightedge (no ruler marks), can you find the exact midpoint of a segment?
- Yes, with two equal arcs
- No, you need to measure
Key idea
Constructions use equal distances, not measurements.
- Step 1The angle at O.
- Step 21. An arc centered at O crosses the sides at A and B.
- Step 32. Equal arcs from A and from B meet at P.
- Step 43. The ray OP bisects the angle (SSS: OAP ≅ OBP).
Worked example
Bisect the angle at vertex O.
Your turn, guided
Your turn: a regular hexagon inside a circle of radius 5 cm. Each side?
Practice ★
- Put the steps for constructing the perpendicular bisector of a segment AB of length 7 cm in order.
- With the compass point on A, draw an arc with a radius of more than half of AB
- Keep the same opening; with the point on B, draw an arc that crosses the first one twice
- Label the two crossing points P and Q
- Draw the line through P and Q with the straightedge
- Put the steps for constructing the perpendicular bisector of a segment AB of length 9 cm in order.
- With the compass point on A, draw an arc with a radius of more than half of AB
- Keep the same opening; with the point on B, draw an arc that crosses the first one twice
- Label the two crossing points P and Q
- Draw the line through P and Q with the straightedge
- To inscribe a regular hexagon in a circle of radius 8 cm, you step the compass around the circle. Which opening do you keep?
- 8 cm, the radius of the circle
- 16 cm, the diameter
- Any opening, as long as it never changes
Watch out!
Practice ★★
- In the construction of the perpendicular bisector of AB (AB = 10 cm), why does the line PQ through the two arc crossings bisect AB at a right angle?
- P and Q are each as far from A as from B, and such points lie on the perpendicular bisector
- Because the angle measures 90° with a protractor
- Because the arcs have a radius of 10 cm
- In the construction of the perpendicular bisector of AB (AB = 7 cm), why does the line PQ through the two arc crossings bisect AB at a right angle?
- P and Q are each as far from A as from B, and such points lie on the perpendicular bisector
- Because the angle measures 90° with a protractor
- Because the arcs have a radius of 7 cm
- A regular hexagon is constructed inside a circle of radius 4 cm, with its vertices on the circle. What is its perimeter, in cm?Not to scale
Exit ticket
Three questions to check you have got it.
- Put the steps for constructing the perpendicular bisector of a segment AB of length 7 cm in order.
- With the compass point on A, draw an arc with a radius of more than half of AB
- Keep the same opening; with the point on B, draw an arc that crosses the first one twice
- Label the two crossing points P and Q
- Draw the line through P and Q with the straightedge
- Put the steps for constructing the perpendicular bisector of a segment AB of length 9 cm in order.
- With the compass point on A, draw an arc with a radius of more than half of AB
- Keep the same opening; with the point on B, draw an arc that crosses the first one twice
- Label the two crossing points P and Q
- Draw the line through P and Q with the straightedge
- Put the steps for constructing the perpendicular bisector of a segment AB of length 6 cm in order.
- With the compass point on A, draw an arc with a radius of more than half of AB
- Keep the same opening; with the point on B, draw an arc that crosses the first one twice
- Label the two crossing points P and Q
- Draw the line through P and Q with the straightedge
Summary card
Constructions
Compass for equal distances, straightedge for lines; justify with congruent triangles.
Watch out: do not change the compass opening between the two arcs.
End of the lesson
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