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About this lesson Algebra I › Functions
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Transformations: shifts and reflections Functions. function notation, domain and range, rate of change, piecewise functions, absolute value, inverse functions
Warm-up Three quick questions from earlier lessons.
Discover Move the sliders and watch the graph of y = ( x − h ) 2 + k y = (x - h)^2 + k y = ( x − h ) 2 + k .
−6 −5 −4 −3 −2 −1 1 2 3 4 5 −4 −2 2 4 6 8
The graph of y = (x − h)² + k, a parabola whose vertex is at (h, k) and moves with the sliders. When h h h goes from 0 to 2, which way does the graph move?
Key idea Changing the rule moves or flips the graph without changing its shape.
y = f ( x − h ) + k y = f(x - h) + k y = f ( x − h ) + k moves the graph of
f f f by
h h h units to the right and
k k k units up.
y = − f ( x ) y = -f(x) y = − f ( x ) reflects it across the
x x x -axis;
y = f ( − x ) y = f(-x) y = f ( − x ) reflects it across the
y y y -axis.
A change inside f ( … ) f(\dots) f ( … ) acts on x x x (horizontally); a change outside acts on y y y (vertically).
Worked example Describe y = ( x + 1 ) 2 − 3 y = (x + 1)^2 - 3 y = ( x + 1 ) 2 − 3 compared with y = x 2 y = x^2 y = x 2 .
1 unit to the left
x + 1 = x − (−1): h = −1.
3 units down
− 3 outside: k = −3.
Vertex:
( − 1 , − 3 ) (-1, -3) ( − 1 , − 3 ) The vertex (0, 0) moves with the graph.
Your turn, guided Your turn: y = ( x − 4 ) 2 + 2 y = (x - 4)^2 + 2 y = ( x − 4 ) 2 + 2 .
4 units to the right
x − 4: h = 4.
The vertex is at
x = 4 x = 4 x = 4
The vertex moves from x = 0 to x = …
Practice ★ The graph of y = x 2 y = x^2 y = x 2 is moved 1 units to the right and 6 units down. Write the equation of the new graph. The graph of y = x 2 y = x^2 y = x 2 is moved 3 units to the right and 1 units down. Write the equation of the new graph. The graph of y = x 2 y = x^2 y = x 2 is moved 4 units to the right and 6 units down. Write the equation of the new graph. The graph of y = x 2 y = x^2 y = x 2 is moved 7 units to the right and 1 units down. Write the equation of the new graph.
Watch out! Zoe described y = ( x + 3 ) 2 y = (x + 3)^2 y = ( x + 3 ) 2 . Tap the line with the mistake.
It is the same parabola as
y = x 2 y = x^2 y = x 2 Correct: a shift does not change the shape.
It is moved 3 units to the right
Wrong: x + 3 = x − (−3). The graph moves 3 units to the left.
Practice ★★ Draw the graph of y = ( x − 1 ) 2 − 3 y = (x - 1)^2 - 3 y = ( x − 1 ) 2 − 3 : place the vertex and one more point. Draw the graph of y = ( x − 1 ) 2 − 1 y = (x - 1)^2 - 1 y = ( x − 1 ) 2 − 1 : place the vertex and one more point.
Match each equation with what it does to the graph of y = f ( x ) y = f(x) y = f ( x ) . y = f ( x ) + 3 y = f(x) + 3 y = f ( x ) + 3 y = f ( x − 3 ) y = f(x - 3) y = f ( x − 3 ) y = − f ( x ) y = -f(x) y = − f ( x ) y = f ( − x ) y = f(-x) y = f ( − x ) moves it up 3 units moves it 3 units to the right reflects it across the x-axis reflects it across the y-axis
Exit ticket Three questions to check you have got it.
The graph of y = x 2 y = x^2 y = x 2 is moved 1 units to the right and 6 units down. Write the equation of the new graph. The graph of y = x 2 y = x^2 y = x 2 is moved 3 units to the right and 1 units down. Write the equation of the new graph. The graph of y = x 2 y = x^2 y = x 2 is moved 4 units to the right and 6 units down. Write the equation of the new graph.
Summary card Shifts and reflections
f ( x − h ) f(x - h) f ( x − h ) : h h h units right. f ( x ) + k f(x) + k f ( x ) + k : k k k units up.− f ( x ) -f(x) − f ( x ) : flip across the x x x -axis. f ( − x ) f(-x) f ( − x ) : flip across the y y y -axis.Inside f ( … ) f(\dots) f ( … ) acts on x x x ; outside acts on y y y . Watch out: f ( x + 3 ) f(x + 3) f ( x + 3 ) moves the graph left.
Answers: Transformations: shifts and reflections A
( x − 1 ) 2 − 6 \left(x - 1\right)^{2} - 6 ( x − 1 ) 2 − 6 ( x − 3 ) 2 − 1 \left(x - 3\right)^{2} - 1 ( x − 3 ) 2 − 1 ( x − 4 ) 2 − 6 \left(x - 4\right)^{2} - 6 ( x − 4 ) 2 − 6 ( x − 7 ) 2 − 1 \left(x - 7\right)^{2} - 1 ( x − 7 ) 2 − 1 B
y = ( x − 1 ) 2 − 3 y = \left(x - 1\right)^{2} - 3 y = ( x − 1 ) 2 − 3 y = ( x − 1 ) 2 − 1 y = \left(x - 1\right)^{2} - 1 y = ( x − 1 ) 2 − 1 C
y = f ( x ) + 3 y = f(x) + 3 y = f ( x ) + 3 → moves it up 3 units · y = f ( x − 3 ) y = f(x - 3) y = f ( x − 3 ) → moves it 3 units to the right · y = − f ( x ) y = -f(x) y = − f ( x ) → reflects it across the x-axis · y = f ( − x ) y = f(-x) y = f ( − x ) → reflects it across the y-axisD
( x − 1 ) 2 − 6 \left(x - 1\right)^{2} - 6 ( x − 1 ) 2 − 6 ( x − 3 ) 2 − 1 \left(x - 3\right)^{2} - 1 ( x − 3 ) 2 − 1 ( x − 4 ) 2 − 6 \left(x - 4\right)^{2} - 6 ( x − 4 ) 2 − 6
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