Sequences and functions

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1. Sequences: explicit and recursive formulas

Warm-up

Three quick questions from earlier lessons.

Discover

A sequence starts 5,8,11,14,…5, 8, 11, 14, \dots Which rule gives the next term from the one before?

  1. Add 3
  2. Multiply by 3

Key idea

A sequence is a function whose inputs are the whole numbers 1,2,3,…1, 2, 3, \dots: ana_n is its nnth term.

An explicit formula gives ana_n from nn directly (for example an=3n+2a_n = 3n + 2). A recursive formula gives a first term and a rule from one term to the next (for example a1=5a_1 = 5, an+1=an+3a_{n+1} = a_n + 3).

Worked example

a1=2a_1 = 2 and an+1=3an−1a_{n+1} = 3a_n - 1. Find a4a_4.

a2=3⋅2−1=5a_2 = 3 \cdot 2 - 1 = 5
Apply the rule to a₁.
a3=3⋅5−1=14a_3 = 3 \cdot 5 - 1 = 14
Then to a₂.
a4=3⋅14−1=41a_4 = 3 \cdot 14 - 1 = 41
Then to a₃.

Your turn, guided

Your turn: an=n2−1a_n = n^2 - 1. Find a5a_5.

a5=52−1a_5 = 5^2 - 1
Replace n by 5.
a5=24a_5 = 24
25 − 1.

Practice ★

  1. an=n2+5a_n = n^2 + 5. Complete the table.
  2. an=n2+9a_n = n^2 + 9. Complete the table.

Watch out!

Practice ★★

  1. a1=3a_1 = 3 and an+1=2an−7a_{n+1} = 2a_n - 7. Find a3a_3.
  2. a1=6a_1 = 6 and an+1=2an−3a_{n+1} = 2a_n - 3. Find a3a_3.
  3. a1=4a_1 = 4 and an+1=2an−6a_{n+1} = 2a_n - 6. Find a3a_3.
  1. Write a formula for ana_n, starting at n=1n = 1: 1,6,11,16,…1,6, 11, 16, \dots
  2. Write a formula for ana_n, starting at n=1n = 1: 3,10,17,24,…3,10, 17, 24, \dots
  3. Write a formula for ana_n, starting at n=1n = 1: 8,14,20,26,…8,14, 20, 26, \dots

Exit ticket

Three questions to check you have got it.

  1. Write a formula for ana_n, starting at n=1n = 1: 1,6,11,16,…1,6, 11, 16, \dots
  2. Write a formula for ana_n, starting at n=1n = 1: 3,10,17,24,…3,10, 17, 24, \dots
  3. Write a formula for ana_n, starting at n=1n = 1: 8,14,20,26,…8,14, 20, 26, \dots

Summary card

Sequences

  • Explicit: ana_n straight from nn.
  • Recursive: a first term and a rule from ana_n to an+1a_{n+1}.

Watch out: check your formula with n=1n = 1.

2. Arithmetic sequences

Warm-up

Three quick questions from earlier lessons.

Discover

A taxi charges 3 dollars, plus 2 dollars per mile. Mile by mile, the fare is 5,7,9,…5, 7, 9, \dots What does the 10th mile cost in total?

  1. 23 dollars
  2. 25 dollars

Key idea

An arithmetic sequence adds the same number dd (the common difference) each time.

an=a1+(n−1)da_n = a_1 + (n - 1)d. From apa_p to aqa_q there are q−pq - p steps, so d=aq−apq−pd = \dfrac{a_q - a_p}{q - p}.

Worked example

An arithmetic sequence has a3=11a_3 = 11 and a8=31a_8 = 31. Find dd and a20a_{20}.

d=31−115=4d = \dfrac{31 - 11}{5} = 4
5 steps from a₃ to a₈.
a1=11−2⋅4=3a_1 = 11 - 2 \cdot 4 = 3
Back 2 steps from a₃.
a20=3+19⋅4=79a_{20} = 3 + 19 \cdot 4 = 79
19 steps from a₁.

Your turn, guided

Your turn: a1=7a_1 = 7, d=5d = 5. Find a12a_{12}.

a12=7+11⋅5a_{12} = 7 + 11 \cdot 5
11 steps.
a12=62a_{12} = 62
7 + 55.

Practice ★

  1. An arithmetic sequence has a1=14a_1 = 14 and common difference 2. Find a43a_{ 43 }.
  2. An arithmetic sequence has a1=17a_1 = 17 and common difference 3. Find a24a_{ 24 }.
  3. An arithmetic sequence has a1=8a_1 = 8 and common difference 5. Find a26a_{ 26 }.
  4. An arithmetic sequence has a1=20a_1 = 20 and common difference 5. Find a28a_{ 28 }.

Watch out!

Practice ★★

  1. In an arithmetic sequence, a4=28a_{ 4 } = 28 and a9=68a_{ 9 } = 68. Find the common difference.
  2. In an arithmetic sequence, a3=18a_{ 3 } = 18 and a7=34a_{ 7 } = 34. Find the common difference.
  3. In an arithmetic sequence, a3=11a_{ 3 } = 11 and a10=25a_{ 10 } = 25. Find the common difference.
  1. What kind of sequence is 3,6,12,24,…3, 6, 12, 24, \dots?
    1. Geometric, with ratio 2
    2. Arithmetic
    3. Neither

Exit ticket

Three questions to check you have got it.

  1. An arithmetic sequence has a1=14a_1 = 14 and common difference 2. Find a43a_{ 43 }.
  2. An arithmetic sequence has a1=17a_1 = 17 and common difference 3. Find a24a_{ 24 }.
  3. An arithmetic sequence has a1=8a_1 = 8 and common difference 5. Find a26a_{ 26 }.

Summary card

Arithmetic sequences

  • Add dd each time: an=a1+(n−1)da_n = a_1 + (n - 1)d.
  • d=aq−apq−pd = \dfrac{a_q - a_p}{q - p}.

Watch out: n−1n - 1 steps from a1a_1 to ana_n.

3. Geometric sequences

Warm-up

Three quick questions from earlier lessons.

Discover

A rumor spreads: 3 people know it on day 1, and each day the number triples. How many know it on day 4?

  1. 81
  2. 12
  3. 243

Key idea

A geometric sequence multiplies by the same number rr (the common ratio) each time.

an=a1⋅r n−1a_n = a_1 \cdot r^{\,n-1}, and r=an+1anr = \dfrac{a_{n+1}}{a_n}.

Worked example

Find a7a_7 for 2,6,18,…2, 6, 18, \dots

r=3r = 3
6 ÷ 2.
a7=2⋅36a_7 = 2 \cdot 3^6
6 multiplications from a₁ to a₇.
a7=1458a_7 = 1458
3⁶ = 729.

Your turn, guided

Your turn: a1=5a_1 = 5, r=2r = 2. Find a6a_6.

a6=5⋅25a_6 = 5 \cdot 2^5
5 multiplications.
a6=160a_6 = 160
5 · 32.

Practice ★

  1. A geometric sequence has a1=3a_1 = 3 and ratio 3. Find a4a_{ 4 }.
  2. A geometric sequence has a1=1a_1 = 1 and ratio 2. Find a8a_{ 8 }.
  3. A geometric sequence has a1=2a_1 = 2 and ratio 3. Find a8a_{ 8 }.
  4. A geometric sequence has a1=4a_1 = 4 and ratio 2. Find a5a_{ 5 }.

Watch out!

Practice ★★

  1. Find the common ratio of the geometric sequence 8,32,128,…8, 32, 128, \dots
  2. Find the common ratio of the geometric sequence 7,21,63,…7, 21, 63, \dots
  1. Write a formula for ana_n, starting at n=1n = 1: 2,8,32,…2, 8, 32, \dots
  2. Write a formula for ana_n, starting at n=1n = 1: 9,36,144,…9, 36, 144, \dots
  3. Write a formula for ana_n, starting at n=1n = 1: 8,40,200,…8, 40, 200, \dots

Exit ticket

Three questions to check you have got it.

  1. Write a formula for ana_n, starting at n=1n = 1: 2,8,32,…2, 8, 32, \dots
  2. Write a formula for ana_n, starting at n=1n = 1: 9,36,144,…9, 36, 144, \dots
  3. Write a formula for ana_n, starting at n=1n = 1: 8,40,200,…8, 40, 200, \dots

Summary card

Geometric sequences

  • Multiply by rr each time: an=a1r n−1a_n = a_1 r^{\,n-1}.
  • rr = a term divided by the one before.

Watch out: the exponent is n−1n - 1.

4. Sigma notation and arithmetic series

Warm-up

Three quick questions from earlier lessons.

Discover

To add 1+2+⋯+1001 + 2 + \dots + 100, pair the first and last terms: 1+1001 + 100, 2+992 + 99, … How many pairs, and what is each pair worth?

  1. 50 pairs of 101
  2. 100 pairs of 101

Key idea

∑k=pqak\displaystyle\sum_{k=p}^{q} a_k means ap+ap+1+⋯+aqa_p + a_{p+1} + \dots + a_q: it has q−p+1q - p + 1 terms.

The sum of the nn terms of an arithmetic sequence is Sn=n(a1+an)2S_n = \dfrac{n(a_1 + a_n)}{2}: the number of terms times the average of the first and last. In particular 1+2+⋯+n=n(n+1)21 + 2 + \dots + n = \dfrac{n(n + 1)}{2}.

Worked example

Find ∑k=120(3k+2)\displaystyle\sum_{k=1}^{20} (3k + 2).

First term 55, last term 6262
k = 1 and k = 20.
S=20(5+62)2S = \dfrac{20(5 + 62)}{2}
20 terms.
S=670S = 670
10 · 67.

Your turn, guided

Your turn: 2+4+6+⋯+402 + 4 + 6 + \dots + 40.

n=20n = 20
40 ÷ 2: 20 terms.
S=420S = 420
20 · 42 / 2.

Practice ★

  1. How many terms does ∑k=317(2k+1)\displaystyle\sum_{k=3}^{ 17 } (2k + 1) have?
  2. How many terms does ∑k=321(2k+1)\displaystyle\sum_{k=3}^{ 21 } (2k + 1) have?
  3. How many terms does ∑k=238(2k+1)\displaystyle\sum_{k=2}^{ 38 } (2k + 1) have?

Watch out!

Practice ★★

  1. Find ∑k=130(3k+7)\displaystyle\sum_{k=1}^{ 30 } (3k + 7).
  2. Find ∑k=111(6k+8)\displaystyle\sum_{k=1}^{ 11 } (6k + 8).
  3. Find ∑k=121(6k+6)\displaystyle\sum_{k=1}^{ 21 } (6k + 6).
  1. Find 1+2+3+⋯+941 + 2 + 3 + \dots + 94.
  2. Find 1+2+3+⋯+801 + 2 + 3 + \dots + 80.

Exit ticket

Three questions to check you have got it.

  1. Find ∑k=130(3k+7)\displaystyle\sum_{k=1}^{ 30 } (3k + 7).
  2. Find ∑k=111(6k+8)\displaystyle\sum_{k=1}^{ 11 } (6k + 8).
  3. Find ∑k=121(6k+6)\displaystyle\sum_{k=1}^{ 21 } (6k + 6).

Summary card

Arithmetic series

  • ∑k=pq\displaystyle\sum_{k=p}^{q} has q−p+1q - p + 1 terms.
  • Sn=n(a1+an)2S_n = \dfrac{n(a_1 + a_n)}{2}.
  • 1+2+⋯+n=n(n+1)21 + 2 + \dots + n = \dfrac{n(n + 1)}{2}.

Watch out: count the terms with +1+1.

5. Finite geometric series

Warm-up

Three quick questions from earlier lessons.

Discover

S=1+2+4+8+16S = 1 + 2 + 4 + 8 + 16. What is 2S−S2S - S?

  1. 32−1=3132 - 1 = 31
  2. 1616

Key idea

Multiplying by rr and subtracting gives the sum of a geometric sequence.

The sum of the first nn terms of a geometric sequence (r≠1r \ne 1) is Sn=a1 rn−1r−1S_n = a_1\,\dfrac{r^n - 1}{r - 1}.

Worked example

Find 3+6+12+…3 + 6 + 12 + \dots (8 terms).

S8=3⋅28−12−1S_8 = 3 \cdot \dfrac{2^8 - 1}{2 - 1}
a₁ = 3, r = 2, n = 8.
S8=3⋅255=765S_8 = 3 \cdot 255 = 765
2⁸ = 256.

Your turn, guided

Your turn: 1+3+9+…1 + 3 + 9 + \dots (5 terms).

S5=35−13−1S_5 = \dfrac{3^5 - 1}{3 - 1}
a₁ = 1, r = 3.
S5=121S_5 = 121
(243 − 1)/2.

Practice ★

  1. Find the sum of the first 6 terms of the geometric sequence with a1=8a_1 = 8 and ratio 3.
  2. Find the sum of the first 5 terms of the geometric sequence with a1=7a_1 = 7 and ratio 2.
  3. Find the sum of the first 5 terms of the geometric sequence with a1=4a_1 = 4 and ratio 2.

Watch out!

Practice ★★

  1. Find ∑k=062k\displaystyle\sum_{k=0}^{ 6 } 2^k.
  2. Find ∑k=0102k\displaystyle\sum_{k=0}^{ 10 } 2^k.
  1. You put 764 dollars in a savings account at the end of each year, at 5 % interest a year. How much is in the account right after the 12th payment? Round to the nearest cent.
  2. You put 344 dollars in a savings account at the end of each year, at 5 % interest a year. How much is in the account right after the 11th payment? Round to the nearest cent.

Exit ticket

Three questions to check you have got it.

  1. Find the sum of the first 6 terms of the geometric sequence with a1=8a_1 = 8 and ratio 3.
  2. Find the sum of the first 5 terms of the geometric sequence with a1=7a_1 = 7 and ratio 2.
  3. Find the sum of the first 5 terms of the geometric sequence with a1=4a_1 = 4 and ratio 2.

Summary card

Finite geometric series

  • Sn=a1 rn−1r−1S_n = a_1\,\dfrac{r^n - 1}{r - 1}.
  • nn is the number of terms; the power is rnr^n.

Watch out: the last term is a1r n−1a_1 r^{\,n-1}, but the sum uses rnr^n.