Local linearization

About this lesson

Calculus AB (AP-aligned) › The derivative

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Local linearization

The derivative.

Warm-up

Three quick questions from earlier lessons.

Discover

The violet curve is y=xy = \sqrt{x}; the blue line is its tangent at x=ax = a. Move aa: near the point of contact, curve and line almost agree.

The curve y = √x and its tangent line at x = a. Near x = a the two are almost the same; farther away the line rises above the curve.

At a=4a = 4 the tangent is L(x)=2+14(x−4)L(x) = 2 + \tfrac{1}{4}(x - 4). Use it to estimate 4.4\sqrt{4.4}.

  1. 2.1
  2. 2.4

Key idea

Near x=ax = a, a differentiable function is almost its tangent line.

The local linearization of ff at x=ax = a is L(x)=f(a)+f′(a)(x−a)L(x) = f(a) + f'(a)(x - a), and f(x)≈L(x)f(x) \approx L(x) for xx near aa. If ff is concave up near aa, LL underestimates; if concave down, it overestimates.

Worked example

f(x)=xf(x) = \sqrt{x}, f′(x)=12xf'(x) = \dfrac{1}{2\sqrt{x}}. Estimate 9.6\sqrt{9.6}.

f(9)=3f(9) = 3, f′(9)=16f'(9) = \tfrac{1}{6}
A nearby point with an exact root: a = 9.
L(9.6)=3+16(0.6)=3.1L(9.6) = 3 + \tfrac{1}{6}(0.6) = 3.1
L(x) = f(9) + f'(9)(x − 9).
9.6≈3.1\sqrt{9.6} \approx 3.1 (true value 3.098…3.098…)
√x is concave down: the estimate is a little too big.

Your turn, guided

Your turn: f(2)=7f(2) = 7 and f′(2)=3f'(2) = 3. Estimate f(2.1)f(2.1).

f(2.1)≈7+3(0.1)=7.3f(2.1) \approx 7 + 3(0.1) = 7.3
L(x) = 7 + 3(x − 2).

Practice ★

  1. f(2)=3f(2) = 3 and f′(2)=2f'(2) = 2. Write the local linearization L(x)L(x) of ff at x=2x = 2.
  2. f(4)=−5f(4) = -5 and f′(4)=−4f'(4) = -4. Write the local linearization L(x)L(x) of ff at x=4x = 4.
  3. f(4)=4f(4) = 4 and f′(4)=−1f'(4) = -1. Write the local linearization L(x)L(x) of ff at x=4x = 4.

Watch out!

Practice ★★

  1. f(x)=xf(x) = \sqrt{x} has f′(x)=12xf'(x) = \dfrac{1}{2\sqrt{x}}. Use the local linearization at x=4x = 4 to estimate 6\sqrt{ 6 }. Give an exact fraction.
  2. f(x)=xf(x) = \sqrt{x} has f′(x)=12xf'(x) = \dfrac{1}{2\sqrt{x}}. Use the local linearization at x=4x = 4 to estimate 8\sqrt{ 8 }. Give an exact fraction.
  1. Near x=4x = 4, the graph of ff is concave up. Does the local linearization at x=4x = 4 over- or underestimate f(x)f(x) for xx near 44?
    1. Underestimate: the tangent line lies below the curve.
    2. Overestimate: the tangent line lies above the curve.
    3. Neither: near x=4x = 4 the linearization is exact.

Exit ticket

Three questions to check you have got it.

  1. f(2)=3f(2) = 3 and f′(2)=2f'(2) = 2. Write the local linearization L(x)L(x) of ff at x=2x = 2.
  2. f(4)=−5f(4) = -5 and f′(4)=−4f'(4) = -4. Write the local linearization L(x)L(x) of ff at x=4x = 4.
  3. f(4)=4f(4) = 4 and f′(4)=−1f'(4) = -1. Write the local linearization L(x)L(x) of ff at x=4x = 4.

Summary card

Local linearization

  • L(x)=f(a)+f′(a)(x−a)L(x) = f(a) + f'(a)(x - a), the tangent line used as an estimate.
  • Good near aa; concave up underestimates, concave down overestimates.

Watch out: multiply the step x−ax - a by the slope f′(a)f'(a).

End of the lesson

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