Expressions, equations and inequalities

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1. Equivalent expressions: distributing and combining like terms

Warm-up

Three quick questions from earlier lessons.

Discover

Is 10−(3+2)10 - (3 + 2) the same as 10−3+210 - 3 + 2?

  1. No
  2. Yes

Key idea

Equivalent expressions are equal for every value of the variable.

Distribute: a(b+c)=ab+aca(b + c) = ab + ac, also with minus signs: −(b−c)=−b+c-(b - c) = -b + c. Combine like terms by adding their coefficients, keeping each term's sign: 5x−2x=3x5x - 2x = 3x. Think of subtraction as adding the opposite.

Worked example

Simplify 6x−2(x−4)+16x - 2(x - 4) + 1.

6x−2x+8+16x - 2x + 8 + 1
−2 times each term.
4x+94x + 9
Combine.

Your turn, guided

Your turn: the coefficient of xx in 7x+3−2x7x + 3 - 2x.

55
7 − 2.

Practice ★

  1. Write 7(x−3)7(x - 3) without parentheses. What is the constant term?
  2. Write 3(x−7)3(x - 7) without parentheses. What is the constant term?
  1. Combine like terms in 9x+6−11x+49x + 6 - 11x + 4. What is the coefficient of xx?

Watch out!

Practice ★★

  1. Simplify 6x−(5x−2)6x - (5x - 2). What is the constant term?
  2. Simplify 7x−(9x−9)7x - (9x - 9). What is the constant term?
  1. Boss problem. A rectangle has sides x+6x + 6 and 3x−53x - 5. Its perimeter is 2(x+6)+2(3x−5)2(x + 6) + 2(3x - 5).

Exit ticket

Three questions to check you have got it.

  1. Write 7(x−3)7(x - 3) without parentheses. What is the constant term?
  2. Write 3(x−7)3(x - 7) without parentheses. What is the constant term?
  3. Write 3(x−2)3(x - 2) without parentheses. What is the constant term?

Summary card

Equivalent expressions

Distribute to every term; combine like terms with their signs.

Watch out: a minus before parentheses changes every sign inside.

2. Solve linear equations in one variable

Warm-up

Three quick questions from earlier lessons.

Discover

A pizza party costs 40 dollars plus 12 dollars per pizza, and the total is 100 dollars. Which equation fits?

  1. 40+12p=10040 + 12p = 100
  2. 12+40p=10012 + 40p = 100

Key idea

Equivalent equations have the same solutions.

To solve a linear equation, make equivalent equations: add or subtract the same amount on both sides, multiply or divide both sides by the same non-zero number, distribute, collect like terms. Stop when xx is alone.

Worked example

Solve 5x+3=2x+155x + 3 = 2x + 15.

3x+3=153x + 3 = 15
Subtract 2x.
3x=123x = 12
Subtract 3.
x=4x = 4
Divide by 3.

Your turn, guided

Your turn: 3(x+2)=213(x + 2) = 21. Find xx.

x=5x = 5
Divide by 3: x + 2 = 7.

Practice ★

  1. Solve 3x+3=−183x + 3 = -18. x=  ?x = \;?
  2. Solve 8x+14=−268x + 14 = -26. x=  ?x = \;?
  1. Solve 4x+8=3x+94x + 8 = 3x + 9. x=  ?x = \;?

Watch out!

Practice ★★

  1. Solve 6(x+4)=306(x + 4) = 30. x=  ?x = \;?
  2. Solve 3(x+4)=333(x + 4) = 33. x=  ?x = \;?

Exit ticket

Three questions to check you have got it.

  1. Solve 3x+3=−183x + 3 = -18. x=  ?x = \;?
  2. Solve 8x+14=−268x + 14 = -26. x=  ?x = \;?
  3. Solve 4x+4=324x + 4 = 32. x=  ?x = \;?

Summary card

Linear equations

Do the same to both sides until xx is alone.

Watch out: distribute to every term.

3. Solve linear inequalities in one variable

Warm-up

Three quick questions from earlier lessons.

Discover

−2x>6-2x > 6. Try x=−4x = -4: −2⋅(−4)=8>6-2 \cdot (-4) = 8 > 6. So which describes all solutions?

  1. x<−3x < -3
  2. x>−3x > -3

Key idea

Solve inequalities like equations, with one extra rule.

Adding, subtracting, multiplying or dividing by a positive number keeps the inequality. Multiplying or dividing by a negative number flips it. Strict signs (<<, >>) exclude the endpoint; ≤\le, ≥\ge include it.

Worked example

Solve −3x+4≤13-3x + 4 \le 13.

−3x≤9-3x \le 9
Subtract 4.
x≥−3x \ge -3
Divide by −3: flip.
[−3,∞)[-3, \infty)
Endpoint included.

Your turn, guided

Your turn: 2x−1<92x - 1 < 9. The boundary value of xx.

x<5x < 5
2x < 10.

Practice ★

  1. Solve 8x+5<458x + 5 < 45. Give the solution set as an interval.
  2. Solve 6x+5<596x + 5 < 59. Give the solution set as an interval.
  1. You have 109 dollars and tickets cost 9 dollars each. Solve 9t≤1099t \le 109: what is the greatest number of tickets you can buy?

Watch out!

Practice ★★

  1. Solve −2x+17≤9-2x + 17 \le 9. Give the solution set as an interval.
  2. Solve −2x+1≤19-2x + 1 \le 19. Give the solution set as an interval.

Exit ticket

Three questions to check you have got it.

  1. Solve 8x+5<458x + 5 < 45. Give the solution set as an interval.
  2. Solve 6x+5<596x + 5 < 59. Give the solution set as an interval.
  3. Solve 7x+9<−547x + 9 < -54. Give the solution set as an interval.

Summary card

Inequalities

Solve as an equation; flip when multiplying or dividing by a negative.

Watch out: check with a number from your answer.

4. Arithmetic sequences

Warm-up

Three quick questions from earlier lessons.

Discover

A taxi charges 3 dollars, plus 2 dollars per mile. Mile by mile, the fare is 5,7,9,…5, 7, 9, \dots What does the 10th mile cost in total?

  1. 23 dollars
  2. 25 dollars

Key idea

An arithmetic sequence adds the same number dd (the common difference) each time.

an=a1+(n−1)da_n = a_1 + (n - 1)d. From apa_p to aqa_q there are q−pq - p steps, so d=aq−apq−pd = \dfrac{a_q - a_p}{q - p}.

Worked example

An arithmetic sequence has a3=11a_3 = 11 and a8=31a_8 = 31. Find dd and a20a_{20}.

d=31−115=4d = \dfrac{31 - 11}{5} = 4
5 steps from a₃ to a₈.
a1=11−2⋅4=3a_1 = 11 - 2 \cdot 4 = 3
Back 2 steps from a₃.
a20=3+19⋅4=79a_{20} = 3 + 19 \cdot 4 = 79
19 steps from a₁.

Your turn, guided

Your turn: a1=7a_1 = 7, d=5d = 5. Find a12a_{12}.

a12=7+11⋅5a_{12} = 7 + 11 \cdot 5
11 steps.
a12=62a_{12} = 62
7 + 55.

Practice ★

  1. An arithmetic sequence has a1=14a_1 = 14 and common difference 2. Find a43a_{ 43 }.
  2. An arithmetic sequence has a1=17a_1 = 17 and common difference 3. Find a24a_{ 24 }.
  3. An arithmetic sequence has a1=8a_1 = 8 and common difference 5. Find a26a_{ 26 }.
  4. An arithmetic sequence has a1=20a_1 = 20 and common difference 5. Find a28a_{ 28 }.

Watch out!

Practice ★★

  1. In an arithmetic sequence, a4=28a_{ 4 } = 28 and a9=68a_{ 9 } = 68. Find the common difference.
  2. In an arithmetic sequence, a3=18a_{ 3 } = 18 and a7=34a_{ 7 } = 34. Find the common difference.
  3. In an arithmetic sequence, a3=11a_{ 3 } = 11 and a10=25a_{ 10 } = 25. Find the common difference.
  1. What kind of sequence is 3,6,12,24,…3, 6, 12, 24, \dots?
    1. Geometric, with ratio 2
    2. Arithmetic
    3. Neither

Exit ticket

Three questions to check you have got it.

  1. An arithmetic sequence has a1=14a_1 = 14 and common difference 2. Find a43a_{ 43 }.
  2. An arithmetic sequence has a1=17a_1 = 17 and common difference 3. Find a24a_{ 24 }.
  3. An arithmetic sequence has a1=8a_1 = 8 and common difference 5. Find a26a_{ 26 }.

Summary card

Arithmetic sequences

  • Add dd each time: an=a1+(n−1)da_n = a_1 + (n - 1)d.
  • d=aq−apq−pd = \dfrac{a_q - a_p}{q - p}.

Watch out: n−1n - 1 steps from a1a_1 to ana_n.

5. Geometric sequences

Warm-up

Three quick questions from earlier lessons.

Discover

A rumor spreads: 3 people know it on day 1, and each day the number triples. How many know it on day 4?

  1. 81
  2. 12
  3. 243

Key idea

A geometric sequence multiplies by the same number rr (the common ratio) each time.

an=a1⋅r n−1a_n = a_1 \cdot r^{\,n-1}, and r=an+1anr = \dfrac{a_{n+1}}{a_n}.

Worked example

Find a7a_7 for 2,6,18,…2, 6, 18, \dots

r=3r = 3
6 ÷ 2.
a7=2⋅36a_7 = 2 \cdot 3^6
6 multiplications from a₁ to a₇.
a7=1458a_7 = 1458
3⁶ = 729.

Your turn, guided

Your turn: a1=5a_1 = 5, r=2r = 2. Find a6a_6.

a6=5⋅25a_6 = 5 \cdot 2^5
5 multiplications.
a6=160a_6 = 160
5 · 32.

Practice ★

  1. A geometric sequence has a1=3a_1 = 3 and ratio 3. Find a4a_{ 4 }.
  2. A geometric sequence has a1=1a_1 = 1 and ratio 2. Find a8a_{ 8 }.
  3. A geometric sequence has a1=2a_1 = 2 and ratio 3. Find a8a_{ 8 }.
  4. A geometric sequence has a1=4a_1 = 4 and ratio 2. Find a5a_{ 5 }.

Watch out!

Practice ★★

  1. Find the common ratio of the geometric sequence 8,32,128,…8, 32, 128, \dots
  2. Find the common ratio of the geometric sequence 7,21,63,…7, 21, 63, \dots
  1. Write a formula for ana_n, starting at n=1n = 1: 2,8,32,…2, 8, 32, \dots
  2. Write a formula for ana_n, starting at n=1n = 1: 9,36,144,…9, 36, 144, \dots
  3. Write a formula for ana_n, starting at n=1n = 1: 8,40,200,…8, 40, 200, \dots

Exit ticket

Three questions to check you have got it.

  1. Write a formula for ana_n, starting at n=1n = 1: 2,8,32,…2, 8, 32, \dots
  2. Write a formula for ana_n, starting at n=1n = 1: 9,36,144,…9, 36, 144, \dots
  3. Write a formula for ana_n, starting at n=1n = 1: 8,40,200,…8, 40, 200, \dots

Summary card

Geometric sequences

  • Multiply by rr each time: an=a1r n−1a_n = a_1 r^{\,n-1}.
  • rr = a term divided by the one before.

Watch out: the exponent is n−1n - 1.