Products and powers in polar form (De Moivre)

About this lesson

Precalculus › Parametric equations and polar coordinates

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Products and powers in polar form (De Moivre)

Parametric equations and polar coordinates. parametric equations, eliminate the parameter, polar coordinates, polar equations, polar form, De Moivre, modulus, argument

Warm-up

Three quick questions from earlier lessons.

Discover

Multiplying by ii turns a point a quarter turn around 0: i⋅1=ii \cdot 1 = i, i⋅i=−1i \cdot i = -1. What does multiplying by 2i2i do to the length and the angle of zz?

  1. Doubles the length and adds 90∘90^\circ
  2. Adds 2 to the length and doubles the angle

Key idea

In polar form, products and powers are easy.

r1(cos⁡α+isin⁡α)⋅r2(cos⁡β+isin⁡β)=r1r2(cos⁡(α+β)+isin⁡(α+β))r_1(\cos\alpha + i\sin\alpha) \cdot r_2(\cos\beta + i\sin\beta) = r_1 r_2\big(\cos(\alpha + \beta) + i\sin(\alpha + \beta)\big): multiply the moduli, add the arguments. De Moivre: (r(cos⁡θ+isin⁡θ))n=rn(cos⁡nθ+isin⁡nθ)\big(r(\cos\theta + i\sin\theta)\big)^n = r^n(\cos n\theta + i\sin n\theta).

Worked example

Compute (2(cos⁡20∘+isin⁡20∘))3\left(2(\cos 20^\circ + i\sin 20^\circ)\right)^3.

23=82^3 = 8
Modulus to the power 3.
3⋅20∘=60∘3 \cdot 20^\circ = 60^\circ
Argument times 3.
8(cos⁡60∘+isin⁡60∘)=4+43 i8(\cos 60^\circ + i\sin 60^\circ) = 4 + 4\sqrt{3}\,i
cos 60° = 1/2, sin 60° = √3/2.

Your turn, guided

Your turn: 3(cos⁡50∘+isin⁡50∘)⋅2(cos⁡40∘+isin⁡40∘)3(\cos 50^\circ + i\sin 50^\circ) \cdot 2(\cos 40^\circ + i\sin 40^\circ).

6(cos⁡90∘+isin⁡90∘)6(\cos 90^\circ + i\sin 90^\circ)
3 · 2 and 50° + 40°.
=6i= 6i
cos 90° = 0, sin 90° = 1: type the result.

Practice ★

  1. z1=2(cos⁡40∘+isin⁡40∘)z_1 = 2\left(\cos 40^\circ + i\sin 40^\circ\right) and z2=4(cos⁡55∘+isin⁡55∘)z_2 = 4\left(\cos 55^\circ + i\sin 55^\circ\right). Find z1z2z_1 z_2 in polar form.
  2. z1=3(cos⁡50∘+isin⁡50∘)z_1 = 3\left(\cos 50^\circ + i\sin 50^\circ\right) and z2=2(cos⁡55∘+isin⁡55∘)z_2 = 2\left(\cos 55^\circ + i\sin 55^\circ\right). Find z1z2z_1 z_2 in polar form.
  3. z1=5(cos⁡30∘+isin⁡30∘)z_1 = 5\left(\cos 30^\circ + i\sin 30^\circ\right) and z2=6(cos⁡45∘+isin⁡45∘)z_2 = 6\left(\cos 45^\circ + i\sin 45^\circ\right). Find z1z2z_1 z_2 in polar form.

Watch out!

Practice ★★

  1. Use De Moivre's theorem to write (cos⁡60∘+isin⁡60∘)2\left(\cos 60^\circ + i\sin 60^\circ\right)^{ 2 } in the form a+bia + bi (exact).
  2. Use De Moivre's theorem to write (cos⁡60∘+isin⁡60∘)4\left(\cos 60^\circ + i\sin 60^\circ\right)^{ 4 } in the form a+bia + bi (exact).
  3. Use De Moivre's theorem to write (cos⁡30∘+isin⁡30∘)6\left(\cos 30^\circ + i\sin 30^\circ\right)^{ 6 } in the form a+bia + bi (exact).

Exit ticket

Three questions to check you have got it.

  1. Use De Moivre's theorem to write (cos⁡60∘+isin⁡60∘)2\left(\cos 60^\circ + i\sin 60^\circ\right)^{ 2 } in the form a+bia + bi (exact).
  2. Use De Moivre's theorem to write (cos⁡60∘+isin⁡60∘)4\left(\cos 60^\circ + i\sin 60^\circ\right)^{ 4 } in the form a+bia + bi (exact).
  3. Use De Moivre's theorem to write (cos⁡30∘+isin⁡30∘)6\left(\cos 30^\circ + i\sin 30^\circ\right)^{ 6 } in the form a+bia + bi (exact).

Summary card

Products and powers in polar form

  • Product: multiply moduli, add arguments.
  • De Moivre: (r cis θ)n=rn cis(nθ)(r\,\mathrm{cis}\,\theta)^n = r^n\,\mathrm{cis}(n\theta).

Watch out: do not raise the real and imaginary parts separately.

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